Given below are two statements.
Statement I: Stannane is an example of a molecular hydride.
Statement II: Stannane is a planar molecule.
In the light of the above statement, choose the most appropriate answer from the options given below

Stannane is $$SnH_4$$, the hydride of tin (Sn). Since tin is a Group 14 element in the p-block, $$SnH_4$$ is formed by covalent bonding between Sn and H atoms, making it a molecular hydride. Hence, Statement I is true.

Now, tin in $$SnH_4$$ has four bonding pairs and no lone pairs on the central atom (Sn uses $$sp^3$$ hybridisation). According to VSEPR theory, four bonding pairs with no lone pairs adopt a tetrahedral geometry, not a planar geometry. Hence, Statement II is false.

Hence, the correct answer is Option C.