For the given hypothetical reactions, the equilibrium constants are as follows: $$X \rightleftharpoons Y; K_1 = 1.0$$, $$Y \rightleftharpoons Z; K_2 = 2.0$$, $$Z \rightleftharpoons W; K_3 = 4.0$$. The equilibrium constant for the reaction $$X \rightleftharpoons W$$ is

Find the equilibrium constant for $$X \rightleftharpoons W$$ given intermediate steps.

$$X \rightleftharpoons Y$$, $$K_1 = 1.0$$

$$Y \rightleftharpoons Z$$, $$K_2 = 2.0$$

$$Z \rightleftharpoons W$$, $$K_3 = 4.0$$

When reactions are added, their equilibrium constants are multiplied. Adding all three:

$$X \rightleftharpoons Y \rightleftharpoons Z \rightleftharpoons W$$

$$K = K_1 \times K_2 \times K_3 = 1.0 \times 2.0 \times 4.0 = 8.0$$

The correct answer is Option (4): 8.0.