A and B take part in a rifle shooting match. The probability of A hitting the target is0.4, while the probability of B hitting the target is 0.6. If A has the first shot, postwhich both strike alternately, then the probability that A hits the target before B hits it is

A

$$\frac{1}{2}$$

B

$$\frac{10}{19}$$

C

$$\frac{2}{3}$$

D

$$\frac{9}{19}$$