Question 35

Weight of C is twice the weight of M. Weight of M is 1/9 of the weight of R. Weight of R is 5/2 of the weight of K. Weight of K is 1/3 of the weight of G. Who is the second lightest?

Solution

Let weight of G = $$3x$$ kg

=> K's weight = $$\frac{1}{3}\times3x=x$$ kg

=> R's weight = $$\frac{5}{2}\times x=2.5x$$ kg

=> M's weight = $$\frac{1}{9}\times2.5x=\frac{5x}{18}$$ kg

=> C's weight = $$2\times\frac{5x}{18}=\frac{5x}{9}$$ kg

$$\therefore$$ C is the second lightest.

=> Ans - (A)

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