Lithium aluminium hydride can be prepared from the reaction of

We need to identify the reactants used to prepare Lithium Aluminium Hydride (LiAlH$$_4$$).

The preparation reaction is:

$$8\text{LiH} + \text{Al}_2\text{Cl}_6 \to 2\text{LiAlH}_4 + 6\text{LiCl}$$

This reaction involves lithium hydride (LiH) reacting with aluminium chloride (Al$$_2$$Cl$$_6$$) in ether solvent to produce LiAlH$$_4$$.

Therefore, LiAlH$$_4$$ is prepared from LiH and Al$$_2$$Cl$$_6$$.

The correct answer is Option 2.