After interchanging which two numbers, the value of the given equation will be ‘4’?
6 + 3 $$\div$$ 9 $$\times$$ 7 - 5

Option (a) 7 and 6

7 + 3 $$\div$$ 9 $$\times$$ 6 - 5
$$7+\frac{3}{9}\times6-5$$
7+2-5

4

We can obtain the required value from this option.

Option (b) 3 and 5

6 + 5 $$\div$$ 9 $$\times$$ 7 - 3

From this, we will get the fractional value which is not possible.

Option (c) 5 and 6

5 + 3 $$\div$$ 9 $$\times$$ 7 - 6

$$5+3\div9\times7-6$$

From this, we will get the fractional value which is not possible.

Option (d) 9 and 5

6 + 3 $$\div$$ 5 $$\times$$ 7 - 9

From this, we will get the fractional value which is not possible.