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Question 35
A is 60% more efficient than B. In how many days will A and B together complete a piece of work if A alone can complete the work in 15 days?
Solution
Time taken by A alone = 15 days
Efficiency of A : B = 100 : 160
= 15 : 24
=> Time taken by B = 24 days
$$\therefore$$ (A + B)'s 1 day's work
= $$\frac{1}{15} + \frac{1}{24}$$
= $$\frac{8 + 5}{120} = \frac{13}{120}$$
$$\therefore$$ Required time = $$\frac{1}{\frac{13}{120}}$$
= $$\frac{120}{13} = 9\frac{3}{13}$$ days
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