A is 60% more efficient than B. In how many days will A and B together complete a piece of work if A alone can complete the work in 15 days?
Time taken by A alone = 15 days
Efficiency of A : B = 100 : 160
= 15 : 24
=> Time taken by B = 24 days
$$\therefore$$ (A + B)'s 1 day's work
= $$\frac{1}{15} + \frac{1}{24}$$
= $$\frac{8 + 5}{120} = \frac{13}{120}$$
$$\therefore$$ Required time = $$\frac{1}{\frac{13}{120}}$$
= $$\frac{120}{13} = 9\frac{3}{13}$$ days
Create a FREE account and get:
Quick, Easy and Effective Revision
By proceeding you agree to create your account
Free CAT Formulae PDF will be sent to your email address soon !!!
