Which two numbers should be interchanged to make the given equation correct?
$$10 + 2 \times 12 \div 6 − 4 = 16$$

$$10+2\times\ \frac{12}{6}-4=16$$

A. 6 and 12

$$10+2\times\ \frac{6}{12}-4=16$$

$$12\times\ \frac{6}{12}-4=16$$

$$\frac{72}{12}-4=16$$

$$6-4=16$$

$$2=16$$

B. 2 and 10

$$2+10\times\ \frac{12}{6}-4=16$$

$$2+10\times\ 2-4=16$$

$$2+20-4=16$$

$$2+16=16$$

$$18=16$$

C. 10 and 4

$$4+2\times\ \frac{12}{6}-10=16$$

$$4+2\times\ 2-10=16$$

$$4+4-10=16$$

$$8-10=16$$

$$-2=16$$

D. 2 and 4

$$10+4\times\ \frac{12}{6}-2=16$$

$$10+4\times\ 2-2=16$$

$$10+8-2=16$$

$$18-2=16$$

$$16=16$$

Hence option D is the correct answer