Question 34

Two numbers are less than a third number by 30% and 37% respectively. How much per cent is the second number less than the first?

Solution

Let the 3 numbers be a,b,c.

Given a is 30% less than c

=>a=(100-30)%c=.7c

Also given b is 37% less than c

=>b=.63c

a-b=(.7c) - (.63c)=.07c

percentage difference between a and b=$$\frac{a-b}{a} \times 100$$%=$$\frac{.07c}{.7c} \times 100$$%=10%

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