Which two signs need to be interchanged to make the following equation correct?

$$2 + 5 − 3 \times 6 \div 2 = 14$$

Option (a) + and $$\div$$

$$2 \div 5 − 3 \times 6 + 2 = 14$$

$$0.4 − 18 + 2 = 14$$

The given equation is not satisfied. Because it will give values in decimals. So this is not the correct answer.

Option (b) $$\times$$ and $$\div$$

$$2 + 5 − 3 \div 6 \times 2 = 14$$

$$2+5\ −\ \frac{3}{6}\times2=14$$

$$2+5\ −\ 1=14$$

$$6\ne\ 14$$

Option (c) − and $$\times$$

$$2 + 5 \times 3 − 6 \div 2 = 14$$

$$2 + 15 − 3 = 14$$

17 − 3 = 14

14 = 14

The given equation is satisfied. So this is the correct answer.
Option (d) + and $$\times$$

$$2 \times 5 − 3 + 6 \div 2 = 14$$

$$10 − 3 + 3 = 14$$

$$10\ne\ 14$$

The given equation is not satisfied. So this is not the correct answer