Sign in
Please select an account to continue using cracku.in
↓ →
Let QRS be a triangular park in xy-plane with side RS = 375 meters and angle QRS = 90°. A pole PQ vertical to the xy-plane is fixed at Q with height PQ = h. if tan PRQ = $$\frac{17}{25}$$ and tan PSQ = $$\frac{8}{25}$$ then the value of h (in meters) is
$$\frac{h}{SQ}=\frac{8}{25}$$
$$\frac{h}{RQ}=\frac{17}{25}$$
=> $$SQ^2=\frac{25^2}{8^2}h^2$$
$$RQ^2=\frac{25^2}{17^2}h^2$$
$$SQ^2=RQ^2+375^2$$
Upon solving, h = 136
Was this solution helpful?
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation