Which two numbers (NOT digits) should be interchanged to make the following equation correct?
$$26 \div 2 + 13 \times 6 − 4 = 10$$

Option (a) 13 and 4

$$26 \div 2 + 4 \times 6 − 13 = 10$$

$$13 + 24 − 13 = 10$$

$$13 + 11 = 10$$

$$24\ne\ 10$$

Option (b) 2 and 13

$$26 \div 13 + 2 \times 6 − 4 = 10$$

$$2 + 12 − 4 = 10$$

10 = 10

The given equation is satisfied. So this is the correct answer.

Option (c) 2 and 10

$$26 \div 10 + 13 \times 6 − 4 = 2$$

$$2.6 + 78 − 4 = 2$$

$$76.6\ne\ 2$$

The given equation is not satisfied. So this is not the correct answer.

Option (d) 2 and 4

$$26 \div 4 + 13 \times 6 − 2 = 10$$

$$6.5 + 78 − 2 = 10$$

$$82.5\ne\ 10$$

The given equation is not satisfied. So this is not the correct answer.