Match List-I with List-II

	List-I		List-II
A	16 g of CH$$_4$$(g)	I	Weighs 28g
B	1 g of H$$_2$$(g)	II	$$60.2 \times 10^{23}$$ electrons
C	1 mole of N$$_2$$(g)	III	Weighs 32g
D	0.5 mol of SO$$_2$$(g)	IV	Occupies 11.4 L volume at STP

Choose the correct answer from the options given below:

Match List-I with List-II for mole concept calculations.

A. 16 g of CH$$_4$$(g):

Molar mass of CH$$_4$$ = 16 g/mol, so 16 g = 1 mole.

Electrons in CH$$_4$$: C has 6e, 4H have 4e = 10 electrons per molecule.

Total electrons = $$1 \times 6.02 \times 10^{23} \times 10 = 60.2 \times 10^{23}$$ electrons = II

B. 1 g of H$$_2$$(g):

Molar mass of H$$_2$$ = 2 g/mol, so 1 g = 0.5 mol.

Volume at STP = $$0.5 \times 22.4 = 11.2 \approx 11.4$$ L (using 22.7 L/mol for updated STP) = IV

C. 1 mole of N$$_2$$(g):

Mass = $$1 \times 28 = 28$$ g. Weighs 28 g = I

D. 0.5 mol of SO$$_2$$(g):

Mass = $$0.5 \times 64 = 32$$ g. Weighs 32 g = III

Matching: A-II, B-IV, C-I, D-III

The correct answer is Option B: A-II, B-IV, C-I, D-III.