In photoelectric effect, the stopping potential $$ (V_0)$$ $$v/s$$ frequency  $$(\nu)$$ curve is plotted. ( $$h$$ is Planck's constant and  $$\phi_0$$  is work function of the metal) $$(A)  V_0$$  $$v/s  \nu$$  is linear. $$(B)$$ } The slope of } $$V_0$$  $$v/s  \nu$$ $$\text{ curve } = \frac{\phi_0}{h}\text{ (C) } h \text{ constant is related to the slope of the}$$  $$V_0$$  v/s  $$\nu $$ line.(D) The value of electric charge of electron is not required to determine  $$h$$ using the  $$V_0$$ v/s  $$\nu$$  curve. $$(E)$$ The work function can be estimated without knowing the value of  h.Choose the correct answer from the options given below:

Analyzing each statement about the photoelectric effect $$V_0$$ vs $$\nu$$ graph:

The photoelectric equation: $$eV_0 = h\nu - \phi_0$$, so $$V_0 = \frac{h}{e}\nu - \frac{\phi_0}{e}$$.

(A) $$V_0$$ vs $$\nu$$ is linear: Yes, it is a straight line with slope $$h/e$$ and intercept $$-\phi_0/e$$. TRUE.

(B) Slope of $$V_0$$ vs $$\nu$$ = $$\phi_0/h$$: The slope is $$h/e$$, not $$\phi_0/h$$. FALSE.

(C) $$h$$ is related to the slope: Slope = $$h/e$$, so $$h = e \times \text{slope}$$. TRUE.

(D) Value of $$e$$ is not required to determine $$h$$: Since $$h = e \times \text{slope}$$, we need the value of $$e$$ to find $$h$$. FALSE.

(E) Work function can be estimated without knowing $$h$$: The x-intercept gives the threshold frequency $$\nu_0 = \phi_0/h$$. To get $$\phi_0$$ in joules, we need $$h$$. However, from the y-intercept: $$-\phi_0/e$$, we can find $$\phi_0/e$$ (in eV) directly from the graph without knowing $$h$$. TRUE.

Correct statements: A, C, E.

The correct answer is Option B: (A), (C) and (E) only.