The number of molecules and moles in 2.8375 litres of O$$_2$$ at STP are respectively

At STP (Standard Temperature and Pressure), 1 mole of an ideal gas occupies 22.7 L (or 22.4 L at old STP).

Using 22.7 L/mol (new STP at 273.15 K, 1 bar):

$$\text{Moles} = \frac{2.8375}{22.7} = 0.125 \text{ mol}$$

Number of molecules:

$$N = 0.125 \times 6.022 \times 10^{23} = 7.527 \times 10^{22}$$

The correct answer is Option 4: $$7.527 \times 10^{22}$$ and 0.125 mol.

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