6 litres of an alkene require 27 litres of oxygen at constant temperature and pressure for complete combustion. The alkene is :

The balanced chemical equation for the complete combustion of an alkene is:

$$C_nH_{2n} + \frac{3n}{2}O_2 \rightarrow nCO_2 + nH_2O$$

$$\frac{\text{Volume of } O_2}{\text{Volume of alkene}} = \frac{3n/2}{1} = \frac{3n}{2}$$

$$\frac{27}{6} = \frac{3n}{2}$$

$$n = \frac{4.5}{1.5} = 3$$

The value $$n = 3$$ corresponds to the molecular formula $$C_3H_6$$, which is Propene.

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