Question 30

Which two numbers need to be interchanged to make the following equation correct?
$$22 โˆ’ 9 \div 5 + 10 \times 1 = 29$$

Solution

$$22-\frac{9}{5}+10\times\ 1=29$$

A. 22 and 10

$$10-\frac{9}{5}+22\times\ 1=29$$

$$10-1.8+22\times\ 1=29$$

$$10-1.8+22=29$$

$$8.2+22=29$$

$$30.2=29$$

B. 5 and 1

$$22-\frac{9}{5}\ +\ 10\times\ 1=29$$

$$22-\frac{9}{1}+10\times\ 5=29$$

$$\frac{13}{1}+10\times\ 5=29$$

$$\frac{13}{1}+50=29$$

$$13+50=29$$

$$43=29$$

C. 10 and 9

$$22-\frac{9}{5}+10\times\ 1=29$$

$$22-\frac{10}{5}+9\times\ 1=29$$

$$22-2+9=29$$

$$20+9=29$$

$$29=29$$

D. 5 and 10

$$22\ -\ \frac{9}{5}+10\times\ 1=29$$

$$22\ -\ \frac{9}{10}+5\times\ 1=29$$

$$\frac{13}{10}+5=29$$

$$1.3+5=29$$

$$6.3=29$$
Hence option C is the correct answer


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App