Question 30

There are eight persons, A, B, C, D, E, F, G and H, all having different weights. Only two persons are lighter than F. F is heavier than A but lighter than B. D is lighter than E but heavier than G. H is lighter than A. C is heavier than E. C is not the heaviest person. The weights of the second heaviest and the second lightest persons are 78 kg and 48 kg, respectively.
How many persons are lighter than the person who is just lighter than D?

Solution

Only two persons are lighter than F.

>>>>>F>>

H is lighter than A. F is heavier than A.

>>>>>F>A>H

D is lighter than E but heavier than G. C is heavier than E. C is not the heaviest person.

>C>E>D>G>F>A>H

Now only B is remaining which can be placed on the blank space.

B>C>E>D>G>F>A>H

The weights of the second heaviest and the second lightest persons are 78 kg and 48 kg, respectively.

B>C(78 kg)>E>D>G>F>A(48 kg)>H

According to the above arrangement, three people are lighter than the person who is just lighter than D.


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