JEE WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
The mass defect in a particular reaction is $$0.4$$ g. The amount of energy liberated is $$n \times 10^7$$ kW h, where $$n$$ = _____. (speed of light $$= 3 \times 10^8 \text{ m s}^{-1}$$)
Correct Answer: 1
$$E = \Delta m \cdot c^2 = 0.4 \times 10^{-3} \times (3 \times 10^8)^2 = 0.4 \times 10^{-3} \times 9 \times 10^{16} = 3.6 \times 10^{13}$$ J.
Converting to kWh: $$\frac{3.6 \times 10^{13}}{3.6 \times 10^6} = 10^7$$ kWh = $$1 \times 10^7$$ kWh.
So $$n = 1$$.
The answer is $$\boxed{1}$$.
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
