Question 30

The HCF of 162, 54 and 135 is:

Solution

The prime factors of given numbers is,

162 - 2 x 3$$^{4}$$

54 - 2 x 3$$^{3}$$

135 - 5 x 3$$^{3}$$

HCF is obtained by multiplying each common prime factor using the least power power of each prime factor

Here common factor is 3 and least power of 3 is 3

So, HCF of given three numbers will be 3$$^{3}$$ or 27

Hence, option C is the correct answer.

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