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Angular impulse:
Angular impulse = change in angular momentum
$$L=r\times p=r\cdot mv$$
$$[L]=[L]\cdot[MLT^{-1}]=[ML^2T^{-1}]$$
So, (A) matches with (III)
Latent heat:
Latent heat = heat per unit mass
$$L=\frac{Q}{m}$$
$$[Q]=[ML^2T^{-2}]$$
$$[L]=\frac{ML^2T^{-2}}{M}=[L^2T^{-2}]$$
So, (B) matches with (I)
Electrical resistivity:
$$R=\rho\frac{L}{A}\Rightarrow\rho=R\frac{A}{L}$$
Now,
$$R=\frac{V}{I}$$
$$[V]=[ML^2T^{-3}A^{-1}]$$
$$[R]=\frac{ML^2T^{-3}A^{-1}}{A}=[ML^2T^{-3}A^{-2}]$$
So,
$$[\rho]=[ML^2T^{-3}A^{-2}]\cdot\frac{L^2}{L}=[ML^3T^{-3}A^{-2}]$$
So, (C) matches with (IV)
Electromotive force (EMF):
EMF has same dimensions as potential difference
$$[EMF]=[ML^2T^{-3}A^{-1}]$$
So, (D) matches with (II)
Final matching:
(A)−(III), (B)−(I), (C)−(IV), (D)−(II)
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