By interchanging which two numbers, the value obtained after solving the given equation will be ’13’?
$$7 + 8 \div 4 \times 3$$

going by the options 

A) 8 and 3

$$7 + 3 \div 4 \times 8$$=  $$7 + \frac{8}{4}\times 3$$ = 7 + 6 = 13 (Option A is correct )

B) 8 and 4

$$7 + 4 \div 8 \times 3$$ =  $$7 + \frac{4}{8}\times 3$$ = 7 + $$\frac{3}{2}$$= $$\frac{17}{2}$$   (option B is incorrect)

c) 7 and 3

$$3 + 8 \div 4 \times 7$$ = 3+$$ \frac{8}{4}\times 7$$ = 3 +14 = 17 (option C is incorrect)

d) 3 and 4

$$7 + 8 \div 3 \times 4$$ = 7+ $$ \frac{8}{3}\times 4$$ = 7 +$$ \frac{32}{3}$$ = $$ \frac{53}{3}$$  (option D is incorrect)