A transistor is connected in common emitter circuit configuration, the collector supply voltage is 10 V and the voltage drop across a resistor of 1000 $$\Omega$$ in the collector circuit is 0.6 V. If the current gain factor $$(\beta)$$ is 24, then the base current is _________ $$\mu$$A. (Round off to the Nearest Integer)

In a common-emitter (C-E) transistor circuit, the current gain factor is $$\beta = \frac{I_C}{I_B}$$, where $$I_C$$ is the collector current and $$I_B$$ is the base current.

Step 1 · Calculate the collector current.
The voltage drop across the collector resistor $$R_C = 1000 \,\Omega$$ is given as $$V_{RC} = 0.6 \text{ V}$$.
Ohm’s law: $$I_C = \frac{V_{RC}}{R_C}$$

$$I_C = \frac{0.6}{1000} \text{ A} = 0.0006 \text{ A} = 0.6 \text{ mA}$$

Convert milliamperes to microamperes:
$$0.6 \text{ mA} = 0.6 \times 1000 \;\mu\text{A} = 600 \;\mu\text{A}$$

Step 2 · Use the current gain relation to find the base current.
$$I_B = \frac{I_C}{\beta}$$

$$I_B = \frac{600 \;\mu\text{A}}{24} = 25 \;\mu\text{A}$$

Therefore, the base current is $$\boxed{25 \;\mu\text{A}}$$ (rounded to the nearest integer).