For every ordinary year number of odd days = 1 odd day
For leap year number of odd days = 2 odd days.
If the odd days sum=7 which implies odd days=0 then again loop starts from 1,2,3,..7.
2008 is clearly a leap year
Therefore,
2005=1 odd day(SUM=1)
2006=1 odd day(SUM=2)
2007=1 odd day(SUM=3),
2008=2 (SUM=5),
2009=1 (SUM=6),
2010=1 (SUM=7),
upto 2010 SUM OF ODD DAYS = 7 which is divisible by 7 and implies next year i.e.,2011 will have same calender as 2005 .
Option C is correct.
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