If the signs $$-$$ and $$\div$$ are interchanged, then which of the following equations would be correct?

Given, 

signs $$-$$ and $$\div$$ are interchanged,

We have to check Option wise and solve as per the rule of BODMAS

Option A : $$8 \times 12 - 6 \div 3 = 12$$

After changing sign : $$8\times12\div6-3=12$$ 

$$\therefore\ 8\times2-3=12$$

$$\therefore\ 13\ne\ 12$$

$$\therefore\ $$ Equation is incorrect.

Option B : $$12 \div 4 \times 3 - 6 = 10$$

After changing sign : $$12-4\times3\div6=10$$

$$\therefore\ 12-4\times\frac{3}{6}=10$$

$$\therefore\ 12-2=10$$

$$\therefore\ 10=10$$

$$\therefore\ $$ Equation is correct. 

Option C : $$4 - 8 \times 16 \div 4 = 6$$

After changing sign : $$4\div8\times16-4=6$$

$$\therefore\ \frac{4}{8}\times16-4=6$$

$$\therefore\ 8-4=6$$

$$\therefore\ 4\ne\ 6$$

$$\therefore\ $$ Equation is incorrect.

Option D :  $$8 + 12 - 6 \div 3 = 9$$

After changing sign : $$8+12\div6-3=9$$

$$\therefore\ 8+2-3=9$$

$$\therefore\ 7\ne\ 9$$

$$\therefore\ $$ Equation is incorrect. 

Hence, Option B is correct.