Magnetic flux (in weber) in a closed circuit of resistance $$20 \text{ }\Omega$$ varies with time $$t$$ (s) as $$\phi = 8t^2 - 9t + 5$$. The magnitude of the induced current at $$t = 0.25 \text{ s}$$ will be ______ mA.

Given: $$\phi = 8t^2 - 9t + 5$$ (in weber), and resistance $$R = 20 \text{ }\Omega$$.

The induced EMF is:

$$\varepsilon = -\dfrac{d\phi}{dt} = -(16t - 9)$$

At $$t = 0.25 \text{ s}$$:

$$\varepsilon = -(16 \times 0.25 - 9) = -(4 - 9) = -(-5) = 5 \text{ V}$$

The magnitude of the induced current:

$$I = \dfrac{|\varepsilon|}{R} = \dfrac{5}{20} = 0.25 \text{ A} = 250 \text{ mA}$$

Therefore, the magnitude of the induced current is $$\boxed{250}$$ mA.