Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
A charge is kept at the central point $$P$$ of a cylindrical region. The two edges subtend a half-angle $$\theta$$ at $$P$$, as shown in the figure. When $$\theta = 30^\circ$$, then the electric flux through the curved surface of the cylinder is $$\Phi$$. If $$\theta = 60^\circ$$, then the electric flux through the curved surface becomes $$\Phi / \sqrt{n}$$, where the value of $$n$$ is ________.
Correct Answer: 3
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.