Equivalent resistance of the following network is ______ $$\Omega$$.

R₁ = 6 Ω is short circuited → ignore it

R₂ = 2 Ω and R₃ = 2 Ω are connected between same two nodes → parallel

R₂ ∥ R₃ = (2×2)/(2+2) = 1 Ω

this is in series with R₄ = 2 Ω

so, (R₂ ∥ R₃) + R₄ = 1 + 2 = 3 Ω

now this 3 Ω is in parallel with R₅ = 3 Ω and R₆ = 3 Ω

so,

$$R_{eq}=3∥3∥3=1Ω$$

final answer: 1 Ω