Solution
Given : $$\tan X$$ = $$\frac{15}{8}$$
Also, $$\tan X=\frac{YZ}{XY}=\frac{15}{8}$$
Let XY = 8 cm and YZ = 15 cm
Thus, in $$\triangle$$ XYZ, => $$(XZ)^2=(XY)^2+(YZ)^2$$
=> $$(XZ)^2=(8)^2+(15)^2$$
=> $$(XZ)^2=64+225=289$$
=> $$XZ=\sqrt{289}=17$$ cm
To find : $$\sin Z=\frac{XY}{XZ}$$
= $$\frac{8}{17}$$
=> Ans - (D)
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