Two satellites $$S_1$$ and $$S_2$$ are revolving in circular orbits around a planet with radius $$R_1 = 3200$$ km and $$R_2 = 800$$ km respectively. The ratio of speed of satellite $$S_1$$ to the speed of satellite $$S_2$$ in their respective orbits would be $$\frac{1}{x}$$ where $$x =$$ ______.

The radii of the circular orbits of the two satellites are given by $$R_1 = 3200$$ km for satellite $$S_1$$ and $$R_2 = 800$$ km for satellite $$S_2$$.

Since the orbital speed of a satellite in a circular orbit of radius $$R$$ is given by $$v = \sqrt{\frac{GM}{R}}$$, where $$M$$ is the mass of the planet, we can derive the ratio of their speeds.

Substituting the given radii into the speed formula yields $$\frac{v_1}{v_2} = \sqrt{\frac{R_2}{R_1}} = \sqrt{\frac{800}{3200}} = \sqrt{\frac{1}{4}} = \frac{1}{2}\,.$$

Comparing this result with the form $$\frac{1}{x}$$, we have $$\frac{v_1}{v_2} = \frac{1}{2}$$, which implies $$x = 2$$. Therefore, the value of $$x$$ is 2.