Question 25
In ΔABC measure of angle B is 90o. If tanA = 15/8, and AB = 0.8cm, then what is the length (in cm) of side AC?
Solution
Given : AB = 0.8 cm and tan A = 15/8
To find : AC = ?
Solution : In right $$\triangle$$ ABC,
=> $$tan(A)=\frac{BC}{AB}$$
=> $$\frac{15}{8}=\frac{BC}{0.8}$$
=> $$BC=\frac{15}{8}\times0.8=1.5$$ cm
$$\therefore$$ $$(AC)^2=(AB)^2+(BC)^2$$
=> $$(AC)^2=(0.8)^2+(1.5)^2$$
=> $$(AC)^2=0.64+2.25=2.89$$
=> $$AC=\sqrt{2.89}=1.7$$ cm
=> Ans - (A)
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