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The order of the oxidation state of the phosphorus atom in $$H_{3}PO_{2},H_{3}PO_{4},H_{3}PO_{3}$$ and $$H_{4}P_{2}O_{6}$$ is
$$H_{3}PO_{3}>H_{3}PO_{2}>H_{3}PO_{4}>H_{4}P_{2}O_{6}$$
$$H_{3}PO_{4}>H_{3}PO_{2}>H_{3}PO_{3}>H_{4}P_{2}O_{6}$$
$$H_{3}PO_{4}>H_{4}P_{2}O_{6}>H_{3}PO_{3}>H_{3}PO_{2}$$
$$H_{3}PO_{2}>H_{3}PO_{3}>H_{4}P_{2}O_{6}>H_{3}PO_{4}$$
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