Question 22
A force $$(3x^2 + 2x - 5) \text{ N}$$ displaces a body from $$x = 2 \text{ m}$$ to $$x = 4 \text{ m}$$. Work done by this force is ______ J.
Correct Answer: 58
Solution
Work = $$\int_2^4 (3x^2+2x-5)dx = [x^3+x^2-5x]_2^4$$
At x=4: 64+16-20 = 60. At x=2: 8+4-10 = 2.
W = 60 - 2 = 58 J.
The answer is $$\boxed{58}$$ J.
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