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The greatest number among $$2^{300}, 3^{200}, 4^{100}, 2^{100} + 3^{100}$$ is
$$4^{100}$$ can be written as $$2^{200}$$ which is less than $$2^{300}$$ .
$$2^{100}+3^{100}$$ < $$2(3^{100})$$ < $$3^{200}$$
Now we have to see which is greatest among $$2^{300}$$ & $$3^{200}$$ .
$$2^{300}$$ = $$2^{3^{100}}$$ = $$8^{100}$$
$$3^{200}$$ = $$3^{2^{100}}$$ = $$9^{100}$$
Therefore, $$3^{200}$$ is greatest among all.
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