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Please calculate in how many ways can a set of five players be formed out of a total of ten players such that two particular players should be involved in each set?
There are total 10 members , from which 2 are always present in the team of 5 to be selected, Hence we have to choose only rest of 3 members from a set of 8 members (10-2) :
$$8_{C_3}$$ = 56 ways.
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