The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What would be the area of a triangle whose base is equal to the diagonal of the rectangle and whose height is equal to the length of the rectangle?
Let the length and breadth be a+6 and a respectively.
2(a+a+6) = 84 => a = 18
height of triangle = 24 and base = 30
Area = $$\frac{1}{2}*24*30$$ = 360 sq m
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