The angles of 1 triangle are in ratio ol 3 : 5 : 1 respectively. What is the difference between twice the smallest angle and the second largest arigle of the triangle
We know that the sum of interior angles of a triangle is equal to $$180^{o}$$.
The total sum of the ratios must be equal to $$180^{o}$$.
Hence each angle of the triangle is $$\frac{3\times180}{9}=60^{o}$$ , $$\frac{5\times180}{9}=100^{o}$$ and $$\frac{1\times180}{9}=20^{o}$$
Twice the smallest angle = $$2 \times 20^{o} = 40^{o}$$
Second largest angle =$$60^{o}$$
Difference = $$60^{o} - 40^{0} = 20^{o}$$
Hence Option E is the correct answer.
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