Question 182

The perimeter of a square is twice the perimeter of a rectangle. If the perimeter of the square is 56 cms. and the length of the rectangle is 9 cms., what is the difference between the breadth of the rectangle and the side of the square ?

Solution

Let side of square be $$a$$.
Length of rectangle be $$l$$ and breadth be $$b$$.
Perimeter of square = $$4\times a=56$$.
$$a=14$$.
Given $$4\times a=2\times2\times \left(l + b\right)$$.
$$a= \left(l + b\right)$$.
Also given $$l=9$$
$$b=a - l = 14 - 9 = 5$$.
$$a - b = 14 - 5 = 9$$.
Hence Option B is the correct answer







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