The ratio of the de-Broglie wavelengths of proton and electron having same kinetic energy:
(Assume $$m_p = m_e \times 1849$$)

The de-Broglie wavelength is given by:

$$\lambda = \frac{h}{\sqrt{2mK}}$$

where $$K$$ is the kinetic energy.

For same kinetic energy:

$$\frac{\lambda_p}{\lambda_e} = \sqrt{\frac{m_e}{m_p}}$$

Given $$m_p = 1849 \times m_e$$:

$$\frac{\lambda_p}{\lambda_e} = \sqrt{\frac{m_e}{1849 \times m_e}} = \frac{1}{\sqrt{1849}} = \frac{1}{43}$$

The ratio $$\lambda_p : \lambda_e = 1 : 43$$.

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The ratio of the de-Broglie wavelengths of proton and electron having same kinetic energy:(Assume $$m_p = m_e \times 1849$$)