The part of work done by A in 1 day is 1/5th of the part of work done by B in 1 day. A’ s 1 day’s work is 3/4th of C’s 1 day’s work. C alone can complete the work in 24 days. In how many days will B alone do the same work ?
C's 1 day's work = $$\frac{1}{24}$$
=> A's 1 day's work = $$\frac{3}{4}$$ * $$\frac{1}{24}$$
= $$\frac{1}{32}$$
=> B's 1 day's work = 5 * $$\frac{1}{32}$$ = $$\frac{5}{32}$$
$$\therefore$$ B alone will finish the work in = $$\frac{32}{5}$$ days
= 6$$\frac{2}{5}$$ days
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