Two trains are moving in the same direction at the speed of 42 km/hr and 84 km/hr, their lengths are 320 metres and 380 metres respectively. What is the time taken (in seconds) by faster train to cross the slower train?
Let time taken = $$t$$ seconds
The trains are moving in same direction, thus relative speed = $$84-42=42$$ km/hr = $$(42\times\frac{5}{18})=\frac{35}{3}$$ m/s
Total distance = sum of lengths of train = $$320+380=700$$ m
Using, time = distance/speed
=> $$t=700\div\frac{35}{3}$$
=> $$t=700\times\frac{3}{35}=60$$ seconds
=> Ans - (A)
Create a FREE account and get:
Quick, easy and effective revision
