Two motorcycles are moving towards each other with the speeds of 38 km/hr and 88 km/hr respectively. One second before the collision what will be the distance (in metres) between the two motorcycles?
The motorcycles are moving towards each other, relative speed = $$38+88=126$$ km/hr
= $$(126\times\frac{5}{18})=35$$ m/s
Thus, one second before the collision, the distance (in metres) between the two motorcycles will be = 35
=> Ans - (D)
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