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RRB NTPC 12 April 2016 Shift 3 Question 16

Question 16

The mean of 10 observations is 17. One more observation is included and the new mean becomes 16. The $$11^{th}$$ observation is

Solution

$$17\times 10=170$$

$$11\times 16=176$$

176-170=6

the 11th observation is 6



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