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Question 16

The magnetic susceptibility of a material of a rod is 499. Permeability in vacuum is $$4\pi \times 10^{-7}$$ Hm$$^{-1}$$. Absolute permeability of the material of the rod is:

The relative permeability of a material is $$\mu_r = 1 + \chi_m$$, where $$\chi_m$$ is the magnetic susceptibility.

Given $$\chi_m = 499$$, we have $$\mu_r = 1 + 499 = 500$$.

The absolute permeability is $$\mu = \mu_r \mu_0 = 500 \times 4\pi \times 10^{-7}$$ Hm$$^{-1}$$.

Computing: $$\mu = 500 \times 4\pi \times 10^{-7} = 2000\pi \times 10^{-7} = 2\pi \times 10^{-4}$$ Hm$$^{-1}$$.

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