A man starts walking from a place X and reaches the place Y in 12 hours. He travels 3/7th of the total distance at the speed of 3 km/hr and the remaining distance at the speed of 4 km/hr. What is the distance (in km) between X and Y?
Let total distance between X and Y = $$7d$$ km
=> Distance travelled at the speed of 3 km/hr = $$\frac{3}{7}\times7d=3d$$ km
Thus, distance travelled at the speed of 4 km/hr =Â $$7d-3d=4d$$ km
Total time taken = 12 hours
Using, time = distance/speed
=> $$\frac{3d}{3}+\frac{4d}{4}=12$$
=> $$d+d=2d=12$$
=> $$d=\frac{12}{2}=6$$
$$\therefore$$ Total distance between X and Y = $$7\times6=42$$ km
=> Ans - (D)
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