A man starts moving from a place A and reaches the place B in 26 hours. He covers 1/3rd of the distance at the speed of 4 km/hr and covers the remaining distance at the speed of 5 km/hr. What is the distance (in km) between A and B?

Let the distance between A and B be = $$3d$$ km

Distance covered at the speed of 4 km/hr = $$\frac{1}{3}\times3d=d$$ km

Thus, remaining distance covered at the speed of 5 km/hr = $$(3d-d)=2d$$ km

Using, time = distance/speed

=> $$\frac{d}{4}+\frac{2d}{5}=26$$

=> $$\frac{(5d+8d)}{20}=26$$

=> $$d=26\times\frac{20}{13}$$

=> $$d=2\times20=40$$

$$\therefore$$ Distance between A and B (in km) = $$3\times40=120$$

=> Ans - (C)