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Question 157
A water glass in the shape of a frustum of a cone of height 14 cm. The diameters at the ends are 4 cm and 2 cm. Then the volume of the glass, in cubic centimeters, is (Take $$\pi = \frac{22}{7}$$)
Solution
The radii would be 2 cm and 1 cm respectively.
Let R = 2 cm and r = 1 cm
Let H = 14 cm
Hence, volume of this frustum is given as
V = $$\frac{\pi}{3}\cdot H\cdot\left(R^2+R\cdot r+r^2\ \right)$$
Substituting the values as declared above, we get
V = 102.667 cubic cm
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