Question 153

The least number which when divided by 6, 9, 12, 15 and 18 leaves the same remainder 2 in each case is :

Solution

The numbers 6,9,12,15,18 leaves same remainder 2 in each case.

So, what we need to do is find the L.C.M. of these numbers and add 2 to it

=> L.C.M. of 6,9,12,15,18 = 180

=> Required no. = 180+2 = 182

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