Question 151

The population of a town at present is 3,00,000. The growth rate of the population in Successive years is expected to be 6%, $$7\frac{1}{2}\%, 9\%, 10\frac{1}{2}\% ....$$ of the present population The expected population at the end of $$8^{th}$$ year from now is

Solution

Population today: 3,00,000

Addition in first year: 18,000
Addition in second year: 22,500
Addition in third year: 27,000
Addition in fourth year: 31,500
Addition in fifth year: 36,000
Addition in sixth year: 40,500
Addition in seventh year: 45,000
Addition in eighth year: 49,500

Hence, population at the end of eighth year = 2,70,000 + 3,00,000 = 5,70,000

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TS Police SI Mains 2018 Arithmetic and Reasoning

The population of a town at present is 3,00,000. The growth rate of the population in Successive years is expected to be 6%, $$7\frac{1}{2}\%, 9\%, 10\frac{1}{2}\% ....$$ of the present population The expected population at the end of $$8^{th}$$ year from now is

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