A bag contains 4 red and 5 black balls. Another bag contains 3 red and 6 black balls. One ball is drawn from the first bag and two balls are drawn from the second bag at random. The probability that out of the three balls. two are black and one is red is

A

$$\frac{5}{18}$$

B

$$\frac{15}{54}$$

C

$$\frac{77}{228}$$

D

$$\frac{25}{54}$$